Inactive Tutor answered 10/29/20
The previous answer correctly listed 2 solutions, namely: x=π/6 and x=5π/6. More trivial solutions x=0 and x=π should be added to the list because of the "inclusive left bracket" in problem description: [0, 2π)
Bella W.
asked 10/29/20Inactive Tutor answered 10/29/20
The previous answer correctly listed 2 solutions, namely: x=π/6 and x=5π/6. More trivial solutions x=0 and x=π should be added to the list because of the "inclusive left bracket" in problem description: [0, 2π)
Inactive Tutor answered 10/29/20
Factor the equation:
tan(x)[1 - 2sin(x)] = 0
Using the zero product rule, set each of the factors equal to zero to solve
a) tan(x) = 0 which has the solution x = 0 or x = π on the interval given
b) 1 - 2sin(x) = 0 or sin(x) = 1/2 which has the solution x = π/6 and x = 5π/6 on the interval given
So the solutions are x = 0, π/6, 5π/6, and π
Tan(x) - 2tan(x)sin(x)=0 Factor out tan x
tanx(1-2sinx)=0
tan x=0 at 0,pi and2pi
1-2sinx=0
-2sinx=-1
sinx=1/2 at pi/6 and 5pi/6
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