Find all solutions on [0, 2π) 6 sin2(x) − 1 sin(x) − 1 = 0

Answer 1

To make this problem easier will make a substitution and let sinx=a which gives us

6a^2-a-1=0 This does not factor so need to use quadratic equation which gives us answers of 1/2 and -1/3 so

sinx = 1/2 x= pi/6 and 5pi/6

sinx= -1/3 (need to use inverse sin function here) x =-.34radians and 3.48 radians