Y = - (1/2) * g * t^2 + Voy * t + Yo
Y = 0
Yo = 68 m
Voy = 0 m/s
Solve for t
t^2 = 2Yo/g
t = 3.72 seconds
Immaculate I.
asked • 10/28/20Kinematics Equation
An object is dropped from a 68 m tall building. How long does it take to reach the ground?
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