X = (1/2)*a*t^2+Vox*t+Xo
Xo = 0
X = 58 m
Vox = 0 m/s
Solve for X
58 = (1/2)*a*3.5^2
a = 9.469 m/s^2
Immaculate I.
asked 10/28/20An object, moving with constant acceleration and zero initial velocity, travels 58 m in 3.5 s. What is the magnitude of its acceleration?
X = (1/2)*a*t^2+Vox*t+Xo
Xo = 0
X = 58 m
Vox = 0 m/s
Solve for X
58 = (1/2)*a*3.5^2
a = 9.469 m/s^2
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