Kinematics Equation

Question

An object is moving with an initial velocity of 30 m/s. It is then subject to a constant acceleration of 4.5 m/s^2 for 9 s. How far will it have traveled during the time of its acceleration?

Answer 1

X = (1/2) *a*t^2+Vox*t+Xo

Xo = 0

X = (1/2) * 4.5*9^2+30*9 = 452.25 m