Given
Q = 8.11 m^3/s
r = 25.9 cm = 0.259 m
Find:
V on each pipe
Solution
Q = VA
r = 25.9 cm = 0.259 m
A = 4 * pi * r^2 = 4 * pi * (0.259)^2 = 0.8429 m^2 (Area of all pipes, that is why it is multiplied times 4)
V = Q/A = 8.11/0.8429 = 9.62 m/s
Zachariah W.
asked 10/26/20Water passes through a main pipe with a flow rate of 8.11 m3/s. The water flow is then equally broken up into 4 smaller pipes, each of radius 25.9 cm. How fast is the water traveling through each of the smaller pipes?
Given
Q = 8.11 m^3/s
r = 25.9 cm = 0.259 m
Find:
V on each pipe
Solution
Q = VA
r = 25.9 cm = 0.259 m
A = 4 * pi * r^2 = 4 * pi * (0.259)^2 = 0.8429 m^2 (Area of all pipes, that is why it is multiplied times 4)
V = Q/A = 8.11/0.8429 = 9.62 m/s
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