Gaukhar M.
asked 10/26/20please help with, couldn't do it. Thank you so much!
a)Find an angle θ with π2<θ<2π that has the same:
Sine as π/6: θ = radians
Cosine as π/6: θ = radians
b)Find an angle θ
Sine function value as 7π/6
θ= radians
Cosine function value as
7π/6
θ= radians
1 Expert Answer
Sin pi/6 would be in Quadrant 2 Where sin is also +. This would be 5pi/6
For cosine pi/6 Angle would be in quadrant 4 where cos is also + This would be 11pi/6
7pi/6 is in quadrant 3 where both sin and cosine are - so for sin 7pi/6 our angle would be in quadrant 4 where sine is also negative. This would be 11pi/6
For cos 7pi/6 we need an angle in quadrant 2 where cosine is also negative
This would be 5p/6
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Gaukhar M.
Thank you so so much!!!! Appreciate you!;)10/26/20