
Mark M. answered 10/25/20
Mathematics Teacher - NCLB Highly Qualified
35000 = 10000e0.15t
3.5 = e0.15t
ln 3.5 = 0.15t
1.252762968 ≈ 0.15t
8.351753123 ≈ t
CHRISTIAN B.
asked 10/25/20How many years will it take for an initial investment of $10,000 to grow to $35,000? Assume a rate of interest of 15% compounded continuously.
It will take about _____ years for the investment to grow to $35,000.
(Round to two decimal places as needed.)
Mark M. answered 10/25/20
Mathematics Teacher - NCLB Highly Qualified
35000 = 10000e0.15t
3.5 = e0.15t
ln 3.5 = 0.15t
1.252762968 ≈ 0.15t
8.351753123 ≈ t
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