What is the speed of the taxi at the top of a 6.00 m radius loop if the intially at rest start location was 32.4 m above the bottom of the loop?

Answer 1

Initially, the taxi has a potential energy corresponding to a height of 32.4 m.

At the top of the loop will have the same total energy, but the potential energy will be for a height of 12 meters (2R) and the rest will be kinetic energy.

Solve for the kinetic energy, then use that to solve for velocity.

Good Luck!