Suppose that f(x)=x^2-4 and g(x)=2x-1. Determine the value of (f*g)(-2)+(f/g)(3)

Answer 1

f(x) = x²-4

g(x) = 2x - 1

(f x g)(-2) + (f⁄g)(3)

(f x g)(-2) = f(-2) x g(-2)

= ((-2)²-4) x ((2(-2)) - 1 )

= (4 - 4) x (-4 - 1) = (0) x (-5) = 0

(f ⁄ g)(3) = f(3) / g(3)

= (3² -4) / (2(3) -1)

= (9 -4) / (6 - 1)

= 5 / 5

= 1

(f x g)(-2) + (f⁄g)(3) = 0 + 1 = 1