Physics question :(

Question

A cat chases a mouse across a 0.98 m high table. The mouse steps out of the way, and the cat slides off the table and strikes the floor 2.9 m from the edge of the table. The acceleration of gravity is 9.81 m/s 2 . What was the cat’s speed when it slid off the table? Answer in units of m/s

Answer 1

A cat chases a mouse across a 0.98 m high table. The mouse steps out of the way, and the cat slides off the table and strikes the floor 2.9 m from the edge of the table. The acceleration of gravity is 9.81 m/s 2 . What was the cat’s speed when it slid off the table? Answer in units of m/s

Let V = speed of cat ( Horizontal )

Vertical speed = 0

The horizontal distance covered = 2.9m

for This motion Speed = distance /time

V = 2.9 / t...... Eq (1)

This time is same as time for free fall from height of 0.98 m

H = 1/2 gt² as Initial vertical velocity is zero

0.98 =0.5 *9.81*t²

t² = 0.98/(0.5*9.81)

Get t from here and plug in Eq 1

to get V