plane travel 45 m/s drops a package from a height of 110 m. aceleration of grav is 9.8 m/s. Where does pckage strike the ground relative to the point directly below where it was released? units of m.

Question

im literally pulling my hair out at this assignment

Answer 1

First, we assume no air resistance and that the plane is flying straight horizontal. When the package is released it has the same 45 m/s horizontal speed as the plane. Now we can find out how long it takes to fall 110 m because its horizontal speed does not affect the time of the fall in any way. height = 1/2gt² so 110 m = 1/2(9.8 m/s/s)t² and solve for t. t = sqrt (110/4.9) = 4.74 seconds.

During that 4.74 seconds, the package was moving sideways (horizontally) at 45 m/s. v = d/t and solve for d. d = (45 m/s)(4.74 s) = 213 m.