f(t)=2t^2; t=5, t=5+h

Question

determine the net change between the given values of the variable.

Answer 1

Given:

f(t)=2t^2

t=5

t=5+h

Solution:

Substitute for t

f(5) = 2t^2

= 2(5)^2

= 2*25

= 50

f(5+h) = 2(5+h)^2

= 2(25 + 10h + h^2)

= 50 + 20h + 2h^2

Their difference is

f(5+h) - f(5) = (50 + 20h + 2h^2) - 50

= 20h + 2h^2

= 2(10h + h^2)

Net Change is 20h + 2h^2