final velocity and acceleration

Question

Two cars both cover a straight distance, d = 268 m, in time t = 29 s. Car A moves at a constant velocity (vA). Car B moves at a constant acceleration (aB), starting from an initial velocity of v0B = 12 m/s. Assume both cars are moving in the positive x-direction.

What is the final velocity of Car B?

What is the acceleration of Car B?

Answer 1

da = db 268 m

t= 29 sec for both

To find Vb ( Final)

Acceleration of car b =?

As A moves with constant velocity

Va = Ditance /time = 268/29 = 9.24m/s

For Car B

Initial Velocity of B = u = 12m/s

Moves for time 29 sec

S = ut +1/2 (at^2) = 12*29 +1/2 a*t² ( where u = Initial velocity of A)

Acceleration of B = - 0.19m/s2 ( It is Deacceleration)

For Final velocity of B If ub = Initial velocity of B, vb + Final velocity of B

Vb = ub +at = 12-0.19 *29 = 12- 5.51= 6.49 m/s= Final velocity of B