find the density of a soda can with the radius of 3.25 cm, a height of 12.2 cm, and a mass of 40 g

Answer 1

Density = Mass/Volume

D=M/V

mass is given

M= 40g

The volume of a soda can is approchâtes by the volume of a cylinder. This is a known formula, given the radius and height of the cylinder.

V (of a cylinder) = πr²h= π*(3.25cm)²*(12.2cm)

V≅404.83cm³≅405cm³

^{(three significant digits would be used here and note that the units are cm cubed)}

Knowing the mass and now the volume, we can find the density.

D=M/V=(40gm)/(405cm³)= 0.098765≅0.0988 gm/cm³

The Density of the soda can is approximately 0.0988 gm/cm³.

Answer 2

ρ = m/V = m/(πr²h) = 40g/(π·3.25²cm²·12.2cm) = 0.0988 g/cm³