Find an equation of the circle that has center (-1,6) and passes through (-6,1)

Answer 1

Equation of a circle is (x-h)² + (y-k)² =r²

Here (h, k) is center and r = radius

Plug in

(-1,6 ) for center

(x+1)² + (y-6)² =r² ..... Eq 1

Now as it also passes through point ( -6,1)

Plug in these values

( -6 +1)² + (1-6)² = r² = 25 +25

you get

r²= 50

Pug this in Eq 1

(x+1)² + (y-6)² =50 This the equation of circle