Hi Shareeka,
Let x = the ten's digit
let y = the units digit
so
10x + y = 3(x+y) + 10 (this says the value of the two digit number is equal to 3 times the sum of the digits + 10
y = 2x +1 (the units digit is 1 more than twice the ten's digit
now substitute this new value for y back in the first equation
10x +(2x+1) = 3(x+2x+1) + 10
12x + 1 = 9x + 13
3x = 12
x = 4
y = 2x +1
y = 9
so our number is
49
49 = 3(4+9) +10
49 = 49
Hope this helps