An object is at rest when it undergoes a constant acceleration of 13m/s2 for 5.0 second. How far will it have traveled during this time?

Answer 1

the position function s(t)=(1/2)(acceleration)(t²)+(initial velocity)(t)+(initial position)

in this case initial velocity and initial position are 0 while acceleration is 13 m/s²

Plug into the equation and you get

s(t)=(1/2)(13)(5²)

s(t)=162.5 meters