Growth in Anville is y =30000(e^.07t)
Brinker is y= 12000(e^.08t)
set these equal to each other and solve for t
30000(e^.07t) = 12000(e^.08t)
2.5= (e^.08t)/(e(.07t)
2.5 = e^.01t
ln 2.5 = ln e^.01t
ln2.5 = .01t
t= ln2.5.0.1= 91.6 years
Gaukhar M.
asked 10/09/20The city of Anville is currently home to 30000 people, and the population has been growing at a continuous rate of 7% per year. The city of Brinker is currently home to 12000 people, and the population has been growing at a continuous rate of 8% per year. In how many years will the populations of the two towns be equal?
years
Growth in Anville is y =30000(e^.07t)
Brinker is y= 12000(e^.08t)
set these equal to each other and solve for t
30000(e^.07t) = 12000(e^.08t)
2.5= (e^.08t)/(e(.07t)
2.5 = e^.01t
ln 2.5 = ln e^.01t
ln2.5 = .01t
t= ln2.5.0.1= 91.6 years
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.