This is continuous growth which utilizes the formula y= A(e^kt) where A is initial value , k is growth constant and t = time
If the investment doubles $6500 will grow to $13000 so
13000= 6500( e^.08t)
2= e^.08t Take natural log of both sides and you get]
ln2 =.08t so t = ln2/.08= 8.66 years
Part b has the same answer