For a submarine to stay submerged, it must be neutrally buoyant, which means it is maintaining a careful balance between its weight and the buoyant force of water pushing it toward the surface.

Question

So it says that the enclosed volume was 977.606 m^3 and that we need to assume the density of the water is 1000 kg/m^3. What I did was

977.606 *1000=977606

and then I multiplied it times the assumed g, which is 9.81 or 9.806.

and I got 9590310 (rounded to the nearest whole number)

I feel like that is completely wrong. Would someone mind checking for me? :)

Answer 1

You have not actually stated what quantity you are trying to calculate. Your answer is also devoid of units.

My best guess is that you are trying to determine buoyant force.

Since buoyant force = weight of the fluid displaced, then

F = 997.606•1000•9.81 should yield the correct value in units of N.

Mr. A