If an arrow is aimed at 45.0° angle, and needs to land 90.4 m away, how fast should it be fired?

Answer 1

Range R= u² sin( 2 theta )/g

For Theta = 45 ,( Range R = 90.4 m given )

R = u²/g

u² =Rg

u = √Rg= √( 90.4* g)

plug in g and get u ( m/s)