College Chemistry Drawing The Structures for IUPAC Names

Question

Draw the Condensed or Expanded structure formula for the following

 4- bromo – 2-pentanone

    Propyl ethanoate

    2-chloro propanamine

Answer 1

If it helps any a description can help:

4 bromo 2 pentanone- you will have a 5 carbon chain and off of the 4th carbon chain there will be bromide atom or group, and off of the second carbon chain you will have a doubly bonded O group or oxygen group.

Propyl ethanoate

The other name is propyl acetate

Propyl is a carbon chain of three so u would have that leading then off of the 3rd carbon chain in propyl you will have coming off of it acetate the ion so off of that last 3rd carbon methyl chain group u would draw C-OOH, the first O doubly bonded off the carbon then the OH group tagged off at the very end of the chain of that carbon.

2 chloro propanamine

This will be a propyl chain group or a chain with 3 methyl groups in a row and off of the 2nd carbon chain you will have Cl branched off and an amine group branched off. Amine is NH2 with R group where it can attach to rest of carbon chain.

Hopefully these descriptions can give you some ideas for a sketch.