(Physics) Tension in a rope and normal force

Question

A wooden box with a mass of 22kg and weight of 216N, is pulled at a constant speed with a rope that makes an angle of 37deg with the wooden floor. A frictional force of 100N resists the motion. What is the tension in the rope and the normal force?

Answer 1

The tension, T, has a horizontal component and a vertical component. The horizontal component is equal to the 100 N or T x cos 37 = 100N. Solving for T gives 125 N. The normal force is the weight of the box minus the upward vertical component of the tension. The equation for this is F_N = W -T x sin37 where F_N is the normal force, W is the weight (216 Newtons), and T is the tension previously calculated. I got 141 N for F_N.