
Yefim S. answered 10/05/20
Math Tutor with Experience
P(x) = 35000 + 1700x; where x number of years after 2003
In 2009 time x = 2009 - 2003 = 6, so P(6) = 35000 + 1700·6 = 45200
Hannah J.
asked 10/05/20A town's population has been growing linearly. In 2003 the population was 35,000. The population has been growing by 1700 people each year.
Write an equation for the population, P, x years after 2003.
P =
Use the formula to find the population in 2009:
Yefim S. answered 10/05/20
Math Tutor with Experience
P(x) = 35000 + 1700x; where x number of years after 2003
In 2009 time x = 2009 - 2003 = 6, so P(6) = 35000 + 1700·6 = 45200
Mark M. answered 10/05/20
Mathematics Teacher - NCLB Highly Qualified
P(x) = 3500 + 1700x
P(6) = 3500 + 1700(6)
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