Right, if we take 18% off, we are left with 82%, right?
12,000 = 22,400(0.82)t
12,000/22,400 = 0.82t
log(15/28) = tlog(0.82)
t = log(15/28)/log(0.82)
t = 3.145 years
Gaukhar M.
asked 10/04/20A vehicle purchased for $22400 depreciates at a constant rate of 18% each year. Its value after t years can be modeled by the equation A=P(0.82)t, where P is the original value of the vehicle.Determine the number of years that it takes for the vehicle to depreciate to $12000
Right, if we take 18% off, we are left with 82%, right?
12,000 = 22,400(0.82)t
12,000/22,400 = 0.82t
log(15/28) = tlog(0.82)
t = log(15/28)/log(0.82)
t = 3.145 years
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Gaukhar M.
oh,wow, that makes sense more. Thank you so much! appreciate your help!10/04/20