Java help with coding

Question

Program that prompts the user for the lengths of the sides of a triangle and

computes the three angles and area. Assume that the user always enters positive integers. To

compute the angles, use the Law of Cosines. To compute the area, use Heron's

formula. Look up these formulas if necessary. Assume that angles A, B, and C are opposite sides a,

b, and c, respectively.

Answer 1

import java.math.*;

class Triangle

{

private double A;

private double B;

private double C;

Triangle ( double a, double b, double c)

{

A=a; B=b; C=c;

}

public double GetA() { return(A); }

public double GetB() { return(B); }

public double GetC() { return(C); }

private double calcAngle( double x, double y, double z)

{

double cosZ = (x*x + y*y - z*z)/(2*x*y); //law of cosines : trig function in terms of sides

return( Math.acos(cosZ)*180/Math.PI); // returns inverse cosine and changes to degrees

}

public double GetAngleA() { return(calcAngle(B,C,A)); }

public double GetAngleB() { return(calcAngle(A,C,B)); }

public double GetAngleC() { return(calcAngle(A,B,C)); }

public double GetArea()

{

double S = (A+B+C)/2;

return( Math.sqrt( S * (S-A)* (S-B)* (S-C) ));

}

public static void main(String args[])

{

Triangle t = new Triangle(5, 9, 13);

System.out.println(" side A measure : "+ t.GetA());

System.out.println(" side B measure : "+ t.GetB());

System.out.println(" side C measure : "+ t.GetC());

double angleA = t.GetAngleA();

double angleB = t.GetAngleB();

double angleC = t.GetAngleC();

double angleSum = angleA+angleB+angleC;

System.out.println(" angle A measure : " + angleA);

System.out.println(" angle B measure : " + angleB);

System.out.println(" angle C measure : " + angleC);

System.out.println(" sum of angles : " + angleSum);

System.out.println(" area = " + t.GetArea());

}

}