I dont know how to solve f(g(11))

Question

f(x)= x^2-6x+3

g(x)= (square root of) x-2

(*all of g(x) is in a sqare root)

What is f(g(11))

Answer 1

For this type of function we have to evaluate doing the inner function first, in this case g(11).

g(x) = √(x-2)

When x = 11, g(11) is √(11-2) = √9 = 3

So g(11) = 3

Now we evaluate the function f(g(11)), knowing that g(11) is 3

f(3) = 3² - 6(3) + 3

f(3) = 9-18+3 = -6

So f(g(11)) = -6

Answer 2

Calculate g(11) first. Since g(x)= sqrt(x-2), g(11)=sqrt(11-2)=sqrt9= = / - 3

f(g(11)) = f(3) or f(-3)

= 3^2 - 6(3) + 3

or

= (-3)^3 - 6(-3) + 3