Yefim S. answered 09/28/20
Math Tutor with Experience
By congugate zeros theorem 1 - 2i is also zero.
Then P(x) = (x - 2)(x + 1)(x - 1 - 2i)(x - 1 + 2i) = (x2 - x - 2)(x2 - 2x + 1 + 4) = (x2 - x - 2)(x2 - 2x + 5) =
x4 - 2x3 + 5x2 - x3 + 2x2 + 5x - 2x2 + 4x - 10 = x4 - 3x3 + 5x2 + 9x - 10