Word Problem... Help!

Question

The length of a new rectangular playing field is 3 yards longer than triple

the width. If the perimeter of the rectangular playing field is 406

yards, what are its​ dimensions?

Answer 1

Hello, Amber,

Set W for width and L for length. We have two unknowns, so we need at least two equations.

we know something about the length:

L = 3W + 3 (the length is 3 times the length plus 3 yards

Perimeter = 2W + 2L

406 yards = 2L + 2W

Substitute the equation for L into the preimeter equation:

406 yards = 2*(3W + 3) + 2W

406 yards = 8W + 6

or

8W = 400 yards

W = 50 yards.

Use this in the first equation to get L, length,

L = 3W + 3

L = 3*(50)+3

L = 153 yards

Check the math:

2W + 2L should equal 406 yards.

2*(50) + 2*(153) = 406 yards.

I hope that helps,

Bob

Answer 2

width=w

length=3w+3

P=2l+2w

406=2(3w+3)+2w

406=6w+6+2w

400=8w

w=50 yds

l=153 yds