A horse pulls a 125 kg cart with a force of 250 N at an angle of 25 degrees.

Question

A horse pulls a 125 kg cart with a force of 250 N at an angle of 25 degrees. If the cart moves with constant velocity, find the friction force, the applied force in both the horizontal and vertical directions, the object's weight, and the normal force. The coefficient of friction is 1.2.

Please include:

1. An FBD
2. Complete solutions showing all of your work
3. A written explanation of 1-2 sentences explaining what your numbers mean

Answer 1

1. As the cart is moving with constant velocity
2. Net force is zero
3. F Cos 25 = µ F Sin25 ( Horizontal forces are balanced) ( Here µ= 1.2 = coefficient of friction )
4. 250 Cos 25 = 1.2*250 sin25
5. Friction force = 1.2 *250 Sin 25
6. Vertical force ( net = 0)
7. Reaction = 250 Sin25
8. 250 Sin25= Weight of cart