Brian A. answered 05/07/25
MS in Clinical Research with TA experience in Biostatistics/ SAS
Question 1. Assume that there are 9 girls and 10 boys in the neighborhood club, and a team of 7 is to be selected. How many different teams can be selected?
Step 1. Permutation or combination.
Ask yourself: Does the order of choosing team members matter? Does the question specify any roles they will take?
No, so the order does not matter, and it is a combination problem.
Step 2. Apply Equation
NCn = N! / n!(N-n)! (Read: Big N (19) choose little n (7))
19C7= 19*18*17*16*15*14*13*12! / 7!(12!)
Note the 12! Divided by another 12!, they cancel out.
19*18*17*16*15*14*13 / 7! = 50,388 different combinations of teams by choosing 7 from 19.
Question 2. How many different teams can be selected if each team must contain exactly 4 girls and 3 boys?
Step 1. Calculate the combinations of teams that have exactly 4 girls from a total of 9 girls (note, this is still a combination question)
NCn = N! / n!(N-n)! (Read: Big N (9) choose little n (4))
9C4= 9*8*7*6*5 / 4!(9-4)!
9C4= 9*8*7*6*5! / 4!*5! (Note 5! Cancel out.)
9C4= 9*8*7*6 / 4! = 126 Combinations of a four-girl team chosen from 9.
Step 2. Calculate the combinations of teams that have exactly 3 boys from a total of 10
NCn = N! / n!(N-n)! (Read: Big N (10) choose little n (3))
10C3 = 10! / 3!(10-3)!
10C3 = 10*9*8*7! / 3!*7! (Note 7! Cancel out)
10C3 = 10*9*8* / 3! = 120 combinations of a three-boy team chosen from 10.
Step 3. Multiply the total combinations of three boy and 4 girl teams.
Combinations of teams with exactly 4 girls and 3 boys: 126*120= 15,120 combinations.