A ball is thrown straight down with a velocity of 12 m/s; what will be its velocity 2.0 s after being released?

Answer 1

v = v₀ + gt = 12m/s + 9.8m/s²·2s = 31.6 m/s

Answer 2

Let v_f be the final velocity, let v_i be the initial velocity, let "a" be the acceleration due to gravity, aka "g" (which is 9.81 m/s²) and let "t" be the time. One of the kinematic equations of motion says:

v_f = v_i + at

v_f = 12 + (9.81)(2.0)

Now just do the arithmetic