Projectile Motion using Vector Geometry

Question

A projectile is launched from the surface at an angle of 30.0° with respect to the horizontal. It lands a distance of 6.0 m away a time of 0.84 s later. Determine the launch velocity of the projectile.

Answer 1

For a projectile, range, R = v₀² sin 2θ / g

6 = v₀² sin 60^o / 9.8

v₀² = 6 x 9.8 / (√3 / 2)

v₀² = 67.9

v₀ = √67.9 = 8.2 m/sec