A newspaper carrier has ​$ in change. He has 2 more quarters than dimes but 5 times as many nickels as quarters. How many coins of each type does he​ have?

Answer 1

Let's let d = the number of dimes, because it is completely unknown.

Then the number of quarters would be q = d + 2.

Finally, the number of nickels would be n = 5q = 5(d + 2).

Re-read the question that you entered and be sure that you understand that we have said the same thing.

By now you should notice that you did not specify a dollar amount.

Without that information, we can only speculate based on what we do know...

1 dime means 3 quarters and 15 nickels --> $1.60

2 dimes means 4 quarters and 20 nickels --> $2.20

3 dimes means 5 quarters and 25 nickels --> $2.60

etc.