Kathy P. answered 09/22/20
Mechanical Engineer with 10+ years of teaching and tutoring experience
PART A: Exponential Growth compounded annually
Use this equation: A = A0*(1+r)^t
19000 = 11000(1+r)^3
(19/11)^(1/3) = (1+r)
1.19983 ~ (1+r)
0.1998 ~ r
PART B: Exponential Growth, compounded continuously
Use this equation: A = A0*e^(rt)
19000 = 11000*e^(3r)
(19/11) = e^(3r)
ln(19/11) = 3r
r = ln(19/11) / 3
r ~ 0.18218