Cooper G.
asked 09/17/20Find two functions f and g such that h(x)= [f o g](x). Neither function may be the identity function f(x)=x.
h(x)= (square root) √(2x-6-1)
h(x)=
Please walk through the steps to solve this as well as the solution
1 Expert Answer
Hi,
I dont think h(x) = √(2x-6-1) is right
it doesn't make sense.
but h(x)= fog(x) = f(g(x)) = √(2x-6-1) I
and we know f(x) = x ------> plug in g(x) in this equation!
f(g(x)) =g(x) II
by compare I and II you figure out left side are the same, so must be right side also will be the same, as a result g(x) = √(2x-6-1) dont care what h(x) is.
Important note : when you need to find fog when f(x) = x always the result is: fog = g :)
I hope it is useful, please let me know if you have any question.
Minoo
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Tom K.
Cooper, rewrite the function using parentheses where needed. I could guess that it is 2x-6 under the square root, and you are taking this to the -1 power, but if this is not the case, I would provide the wrong answer.09/17/20