Mehdi R. answered • 09/16/20
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As we know: V2 - V02 = 2(-g) (Y) , Y is distance between V and V0 , The sign of g is negative because when baseball goes up, its speed decreases.
At maximum height, velocity is zero (V = 0).
-V02 = 2(- g) H → Ymax = H = V02 / 2g → H = (12.1)2 / (2*9.80) → H = 7.5 m
Mehdi R.
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Y = -(g/2) (t^2) + (12.1)t → (H/2) = -4.9(t^2) +(12.1)t →
-4.9(t^2) +(12.1)t - (H/2) = 0 , This is a quadratic equation which has two answers for time that passes from half maximum. One time when baseball goes up and second time, when baseball is going down from its half maximum. (t = 0.36 s and t = 2.1 s)
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09/17/20
Jesus S.
Wow, thank you!
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09/17/20
Jesus S.
How would we find at what times the ball passes through half the maximum height? Time is never given, is it?09/17/20