Arturo O. answered 09/18/20
Experienced Physics Teacher for Physics Tutoring
Use the kinematic relation
v2 - v02 = 2ad ⇒
d = (v2 - v02) / (2a)
Plug in
v = 2.5 m/s
v0 = 1.20 m/s
a = 0.140 m/s2
and get d in meters.
Jesus S.
asked 09/16/20A sperm whale can accelerate at about 0.140 m/s^2 when swimming on the surface of the ocean. How far will it travel if it starts at a speed of 1.20 m/s and accelerates to a speed of 2.5 m/s? Assume the whale travels in a straight line.
Arturo O. answered 09/18/20
Experienced Physics Teacher for Physics Tutoring
Use the kinematic relation
v2 - v02 = 2ad ⇒
d = (v2 - v02) / (2a)
Plug in
v = 2.5 m/s
v0 = 1.20 m/s
a = 0.140 m/s2
and get d in meters.
Frank A. answered 09/17/20
Knowledge, experience and insight from decades of teaching physics.
Hi Jesus S,
A sperm whale can accelerate at about 0.140 m/s^2 when swimming on the surface of the ocean. How far will it travel if it starts at a speed of 1.20 m/s and accelerates to a speed of 2.5 m/s? Assume the whale travels in a straight line.
x = ? (m)
vi = 1.2m/s
vf = 2.5m/s
a = 0.140 m/s2
2•a•x = vf2 -vi2
Rearranging
x = (vf2 - vi2)/2 •a
substituting values from the given data
x = (2.52-1.22)/(2•0.140) = 17.2m
For further clarification or if you need one-on-one tutoring, let me know
Mr. A
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