Dr Gulshan S. answered 09/15/20
Physics Teaching is my EXPERTISE with assured improvement
Hello
At 45 degree Range is Max So Horizontal range up to the level of Table = u2/g = 3.5*3.5/g
An additional distance covered = for falling 1m with horizontal speed of uCos 45= u/√2
time for 1m fall with zero vertical speed = t= √(2/g)
Additional horizontal distance = (u/√2)/√(2/g) = u2/2g
So total distance coveerd before touching the ground = (3.5*3.5 /g +3.5*3.5/2g ) m