Patrick B. answered 09/15/20
Math and computer tutor/teacher
y = (x-1)/[2(x-2)]
vertical asymptote at x=2: (x-2) appears in denominator
zero solution at x=1: (x-1) appears in numerator
Horizontal asymptote at y = 1/2 ---> limit must be 1/2 as x-->infinity
k * lim x-1
----- = 1/2
x-2
k * 1 = 1/2 <-- L'hopital's;s rule or divide everything by x
k=1/2
you can do (1 - 1/x) over (1 - 2/x)
then as x-->infinity, the limit is 1,
so k=1/2
the rational function is y = (x-1)/[2(x-2)] = (x-1)/(2x-4)