
Patrick B. answered 09/13/20
Math and computer tutor/teacher
order O(n^2)
For i=1 to n-1 <-- n
For j=0 to n-i-1 <-- n/2 on average
n(n/2) = n^2/2 so order O(n^2)
Prachi K.
asked 09/13/20For i=1 to n-1
For j=0 to n-i-1
If a[j] > a[j+1] then
Set temp=a[j]
Set a[j]=a[j+1]
Set a[j+1]= temp
Patrick B. answered 09/13/20
Math and computer tutor/teacher
order O(n^2)
For i=1 to n-1 <-- n
For j=0 to n-i-1 <-- n/2 on average
n(n/2) = n^2/2 so order O(n^2)
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