Dr Gulshan S. answered 09/10/20
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Elevator moving down
T1 = 5.64 g - 5.64 *a
a==1.35 m/s2
use g= 10
T2 = (2.82g - 2.82*1.35 ) N
Elevator going up
T1 = 5.64 g +5.64 *1.35
When will the upper string break?
0.88 = 5.64g + 5.64 a
Get a from this equation , which is the maximum acceleration before the upper string breaks

Dr Gulshan S.
09/11/20