
Rajat S. answered 09/05/20
I can teach you physics because I use physics in my work
Hydrostatic pressure = P = r * g * h
r (rho) is the density of the fluid,
g is the acceleration of gravity
h is the height of the fluid above the object
At any point in the pool the density of water and the value of g are the same. So you realize that hydrostatic pressure in the pool only depends on the depth of the point you are measuring.
Also, remember that hydrostatic pressure is equal in all directions at that point. So the bottom of the pool will experience pressure from the column of water directly above it.
3.3 feet is 1 meter.
Issue here is that the pool has a shallow and a deep end. It's split in the middle. So half the pool has pressure of (1000 Kg/m3) * (9.8 m/s2)*(1) = 9800 Kg/m2/s2
and twice that in the area where the depth is 6.6 feet