Inactive Tutor answered 09/04/20
Ex = -∂V/∂x = -3x2y2
Ey = -∂V/∂y = -2x3y
Ez = 0 since V does not depend on z
Now plug in x=4 and y=2 and get
Ex = -3(4)2(2)2 = -192 volts/m
Ey = -2(4)3(2) = -256 volts/m
Answer (c) is correct.
Lin T.
asked 09/04/20If the electrical potential is V=x3y2 Volt at any point of an cartesian coordinate system, what is the electrical field at (x,y,z)=(4,2,1) metres.
a) -192i -256j -12k
b) 0
c) -192i -256j
d) -64y2i -4x3j
e) -64x3i -192y2j
I think the answer is "d)" but I can't be sure.
Inactive Tutor answered 09/04/20
Ex = -∂V/∂x = -3x2y2
Ey = -∂V/∂y = -2x3y
Ez = 0 since V does not depend on z
Now plug in x=4 and y=2 and get
Ex = -3(4)2(2)2 = -192 volts/m
Ey = -2(4)3(2) = -256 volts/m
Answer (c) is correct.
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