Inactive Tutor answered 09/04/20
Tutor
New to Wyzant
N * n/2 on average
Prachi K.
asked 09/04/20void fun(int n, int arr[ ])
{
int i, j, k=0;
for(; i<n ;++i)
while(j<n && arr[i]< arr[j ])
j++;
}
Inactive Tutor answered 09/04/20
N * n/2 on average
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