Linda drove 4 hours. The traffic was heavy on the trip home and slowed her adverage speed by 6mi/hour. The return trip took 4.5 hour. How last did she drive

Question

algebraically determine her adverage speed in each direct 

Answer 1

Let x = speed on first part of the trip

   x - 6 = speed on second part of the trip

 

Distance = (rate)(time)

 

Since the distances each way are the same, we have

 

4x = 4.5(x - 6)

4x = 4.5x - 27

-0.5x = -27

      x = 54

 

The speeds were 54 mph and 48 mph