Assume that the mirror is placed at distance d m from mirror.
So distance of image from mirror = d + 2.4 m
Let's use cartesian sign convention in mirror equation:
u = -d, v = -(d+2.4)
The image is 3 times magnified. so (d+2.4)/d = 3 or d = 1.2
So mirror must be placed 1.2m beyond the lamp.
1/u + 1/v = 1/f or - 1/1.2 + (-1/3.6) = 1/f or - 4/.3.6 = 1/f or f = -.9
Radius of curvature of the mirror is 2f = 1.8 m