Physics (day 2) question #3

Question

A 0.16 kg cricket ball is thrown horizontally at 30 m/s and after it is struck by a cricket paddle, it travels at -30 m/s. If the contact time of the paddle and the ball was 0.0007 seconds, what was the average force the paddle exerted in the ball?

Answer 1

C hange of impulse m(v - v₀)= FΔt; So F = m(v - v₀)/Δt = 0.16kg(30m/s - (- 30)m/s)/0.0007s = 13714.29 N