Jon P. answered 02/11/15
Tutor
5.0
(173)
Studied honors physics at Harvard, worked with many physics students
The odd numbers greater than 1 and less than 9 are 3, 5, and 7.
Multiply 3 x 5 x 7 to get 105. Add 1 to that to get 106. Divide 106 by 3, 5, and 7 and you will get a remainder of 1 each time.
Now, divide 106 by ANY even number and you can't get a remainder of 1. The only way to get a remainder of 1 when dividing by an even number is if you start with an odd number, which 106 is not.
So the answer is $106.
Jon P.
tutor
It's a starting point to find a number that gives a remainder of 1 when you divide by each of them.
When you multiply the numbers together, you get a number that is a multiple of all of them -- 105. Therefore when you divide 105 by each of the numbers 3, 5, and 7, the remainder will be 0. Now add one, to get 106. Now you have a number that gives a remainder of 1 when divided by each of the 3 numbers. That's what the problems asks you to find.
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10/02/15
Shoobie L.
On the bottom it says explain your solution and how you know it is the only correct answer
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03/20/20
Yanifred G.
10/01/15